Friday, July 31, 2009

Firebug AJAX Reading...

Want to read an async AJAX request in FireBug console?


AJAX=new XMLHttpRequest();
AJAX.open( 'POST', 'www.YourUrl.com', true );
AJAX.send( 'postKey=postVal' );
AJAX.onreadystatechange = function(){ console.log( AJAX ); }


This prints everything, not just a successful response. Very useful for learning about the XMLHttpRequest object and reading POST responses inside an authenticated session without any cross-domain trickery.

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